x-4/x^2-6x+8=x/3x+12

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Solution for x-4/x^2-6x+8=x/3x+12 equation: 



x-4/x^2-6x+8=x/3x+12

We move all terms to the left:

x-4/x^2-6x+8-(x/3x+12)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 3x+12)!=0

x∈R



We add all the numbers together, and all the variables

-5x-4/x^2-(x/3x+12)+8=0

We get rid of parentheses

-5x-4/x^2-x/3x-12+8=0

We calculate fractions

We do not support expression: x^3

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